CBSE Set Qa2 Biology Sample Test Papers For Class 12th for students online
You are on answers 20 to 30
Q20. What are
linked genes? Diagrammatically represent a cross between a white eyed female and
red eyed male drosophila.
Ans20. Genes, which tend to move together; that is, appear to be
‘linked’ together occur on the same chromosome and are called ‘linked
genes’. A pair of genes may be identified as linked if their recombination
frequency in a test-cross is lower than the expected value of 50 per cent.
Q21. How does an
excess of tryptophan cause ‘Switching off’ of the ‘tryptophan operon’?
Ans21. Tryptophan Operon consists of five genes coding for five enzymes
catalyzing the synthesis of tryptophan and thus constitute an anabolic pathway.
The regulator R gene produces a protein, referred to as Apoepressor, which
itself is unable to bind to operator O unless its Co-repressor Tryptophan is
present. When Tryptophan is present, the functional repressor forms and binds to
the operator. This binding prevents the transcription of the operon and
production of tryptophan.
Q22. If
abiotic origin of life is in progress on a planet other than earth, what should
be the condition there? Explain.
Ans22. If abiotic origin of life is in progress on a planet other than
the earth, the conditions there should be same as the one prevalent on the
primitive earth. Thus the following conditions would be required :
Solids, liquids, and gases coexist. The atmosphere should be reducing.
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Hydrogen, nitrogen, water vapour, carbon dioxide, methane, and ammonia should be present.
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Sources of energy such as thermal energy, radiation, and lightning should be present.
Q23. Trace the
formation of Ovum from oogonium.
Ans23. Ova form in the ovary. The maturing Graffian follicle contains a
diploid (2n) Primary Oocyte. It undergoes meiosis I to produce two haploid cells
: a larger one, the secondary oocyte and a small Polar body. During meiosis I of
the primary oocyte, the Graffian follicle comes on the ovarian surface.
Immediately after the meiosis I the follicle ruptures and ejects the secondary
oocyte near the open end of the Fallopian tube. As the secondary oocyte moves
down the Fallopian tube, the oocyte starts the meiosis II, though it does not
complete unless the sperm enters the secondary oocyte. Meiosis
II gives a haploid mature ovum and a second polar body.
Q24. Describe
the role of red blood cells in the transport of oxygen and carbon dioxide by
blood.
Ans24. Blood transports oxygen with the help of haemoglobin in RBCs and
carbon dioxide with the help of cytoplasm of red blood cells. Oxygen diffuses
into the RBCs and combines loosely with the Fe2+ ions of
hemoglobin to form oxyhaemoglobin. A lower PO2 and
higher PCO2 in the tissues causes dissociation
of oxyhaemoglobin to deoxyhaemoglobin (reduced haemoglobin)
and molecular oxygen.
Carbon dioxide diffuses into RBCs and reacts with water in the cytoplasm, to
form Carbonic acid :
CO2 + H2O = H2CO3, The reaction is
catalysed by zinc containing Carbonic Anhydrase.
In RBCs carbonic acid forms bicarbonate :
H2CO3 H++HCO3-
Some of the bicarbonate remains in the RBCs but most of it comes out in plasma.
Some of the CO2 reacts with globin of deoxyhaemoglobin to form
Carbaminohaemoglobin in RBCs.
Q25. Draw a diagram to show the internal structure of the
human heart. Label six parts in all including at least three valves.
Ans25.
Q26. What is
metastasis? List any four danger signals of cancer.
Ans26. A malignant tumour does not remain confined to the original tissue.
Cancerous cells are carried by the blood and lymph to other parts of the body,
where they multiply to produce secondary malignant growths. The spread of
cancerous cells to distant sites is termed Metastasis.
Some danger signals of cancer are :
A lump or hard area in the breast.
A change in a wart or mole.
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A persistent change in digestive and bowel habits.
A persistent cough or hoarseness.
Q27. By providing one example for each category, classify
the angiospermic flowers based on the position of ovary.
Ans27. There are three type of flowers in angiosperm, based on the
disposition of floral parts with respect to ovary. They are :
Hypogynous flowers : In such flowers the ovary is superior that is, the
ovary is situated on the torus above all the other floral parts. Examples are:
Musturd and Tomato.
Perigynous flowers : In such flowers the thalamus forms a cup-shaped
structure around the ovary and bears sepals, petals, and stamens. The ovary
appears sunken in these cases, for example in rose.
Epigynous flowers : In such flowers the thalamus is not only cup-shaped
but is fused with the ovary such that the other floral parts arise on the top of
the ovary. The ovary in these cases is inferior. Examples are: Cucumber, Apple.
Q28. Describe
the process of DNA replication.
Ans28. The DNA replication occurs in the following steps :
Origin :
Replication starts from specific positions in the DNA helix, called
‘Origin’. When the replication starts the DNA strands uncoil to expose the
template surface for synthesis of daughter strands on them. Helicase enzymes
help in unwinding the helix and Topoisomerases break and reseal one strand of
DNA to avoid supercoiling. The double stranded DNA unwinds as a Y-shaped
structure called ‘Replication fork’.
Primer formation : A short stretch of RNA is formed on the DNA template,
which serves as the primer for the DNA synthesis. Primase catalyzes the
synthesis of RNA on the existing DNA.
DNA synthesis : DNA polymerase enzyme adds the building blocks to the
primer in a sequence as influenced by the template in 5’ to 3’ direction.
On the parental 5’-3’ strand daughter-strand forms continuously in 5’ –
3’ direction; but on the parental 3’ – 5’ strand daughter-strand forms
discontinuously in short stretches of 5’ – 3’ fragments, called ‘Okazaki
Fragments’. These fragments are then joined together. The continuous
daughter-strand is called ‘Leading strand’, and the discontinuous
daughter-strand is called ‘Lagging strand’. DNA Polymerase has proof-reading
capacity and goes-back to any wrong base and removes it to put new base in its
position before it moves to a new base in 5’ – 3’ direction. As the new
strands grow from the fork and the replication proceeds, the point of divergence
at the replication fork moves away from origin.
Q 29Specify how C4 photosynthetic
pathway increases CO2 concentration in bundle sheathcells of
sugarcane. How much is C4 pathway more energy-expensive than C3
pathway?
Ans29. C4pathway is the one in which carbon
dioxide is fixed in the mesophyll cells and the initial product is a 4-Carbon
compound unlike the Calvin cycle whgich is referred to as C3 pathway
because the first product after CO2 fixing is a 3-carbon compound.
The carbon dioxide acceptor in C4
pathway is a 3-Carbon compound, Phosphoenolpyruvate (PEP) and it forms
4-carbon compound oxaloaceticacid (OAA) by accepting CO2 in
outer mesophyll cells. OAA is converted to malic acid, which is transported to
cells surrounding the vascular bundle, the Bundle sheath cells. Here malic acid
is converted to pyruvic acid and CO2 is released in the cytoplasm.
Thus the concentration of CO2 increases in the bundle
sheath cells.
The pyruvic acid generated in the
bundle sheath cells is transferred back to the mesophyll. It is converted to PEP
by the expenditure of an ATP molecule. But this conversion generates AMP (and
not ADP, as is normal) causing requirement of two additional ATPs to regenerate
AMP. The total additional requirement of ATPs per six CO2 molecules
is thus 12 ATPs in comparison to C3 pathway.
The C4 pathway is thus more energy-expensive than C3 pathway. The C3 pathway requires 18 ATPs for synthesis of one molecule of glucose as against C4 pathway which requires 30 ATPs.
Q30. What is a
synapse? How is the nerve impulse transmitted across a synapse?
Ans30. Synapse is the junction between two neurons, across which the impulse
has to pass from one neuron to the next. Synapses are formed between the axon
terminals of one neuron and the dendrites, the cell body or even sometimes the
axon of one or more neurons. There is no actual continuity between neurons at
the synapse. The axon of a neuron divides near its
termination into many branches, each branch losing its myelin sheath before
termination.
These axon terminals of a neuron then end in expanded feet-like forms on the
dendrites or the cell body of another neuron; there is a narrow fluid-filled
space, called Synaptic cleft, separating the membranes of the two neurons at the
synapse. The axon terminal contains many membrane-bound vesicles, called
Synaptic Vesicle, in its cytoplasm. Within these vesicles, chemical substances,
such as adrenaline and acetylcholine remain stored.
When a nerve impulse passes the axon
terminal, its synaptic vesicles release their stored chemicals to the synaptic
cleft. These diffuse through the cleft to reach the membrane of the next neuron,
and stimulating the latter. This causes the nerve impulse to be transmitted
along the next neuron.